13) co₂ # of molecules:______ # of elements:______ name of element: # of atoms: ______ ______ total # of atoms:______ the #2 is a______ (coefficient or subscript) 14) 3cacl₂ # of molecules:______ # of elements:______ name of element: # of atoms: ______ ______ total # of atoms:______ the #3 is a______ (coefficient or subscript) 15) cr(nh₃)₆(no₃)₃ # of molecules:______ # of elements:______ name of element: # of atoms: ______ ______ total # of atoms:______ the #6 is a______ (coefficient or subscript) 16) 5al(c₂h₃o₂)₂ # of molecules:______ # of elements:______ name of element: # of atoms: ______ ______ total # of atoms:______ the #2 is a______ (coefficient or subscript)

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Accepted Answer

# Explanation:
## Step1: Analyze $CO_2$
- **Number of molecules**: In $CO_2$, the coefficient is $1$ (implied if not written), so the number of molecules is $1$.
- **Number of elements**: $CO_2$ has two elements, carbon ($C$) and oxygen ($O$).
- **Number of atoms**:
    - For carbon ($C$): There is $1$ carbon atom.
    - For oxygen ($O$): The subscript $2$ means there are $2$ oxygen atoms.
    - Total number of atoms: $1 + 2=3$.
- **Role of $2$**: The $2$ is a subscript as it indicates the number of oxygen atoms in the $CO_2$ molecule.

## Step2: Analyze $3CaCl_2$
- **Number of molecules**: The coefficient $3$ indicates there are $3$ $CaCl_2$ molecules.
- **Number of elements**: $CaCl_2$ has two elements, calcium ($Ca$) and chlorine ($Cl$).
- **Number of atoms**:
    - For calcium ($Ca$): In each $CaCl_2$ molecule, there is $1$ calcium atom. For $3$ molecules, $3\times1 = 3$ calcium atoms.
    - For chlorine ($Cl$): The subscript $2$ means in each $CaCl_2$ molecule, there are $2$ chlorine atoms. For $3$ molecules, $3\times2=6$ chlorine atoms.
    - Total number of atoms: $3 + 6=9$.
- **Role of $3$**: The $3$ is a coefficient as it indicates the number of $CaCl_2$ molecules.

## Step3: Analyze $Cr(NH_3)_6(NO_3)_3$
- **Number of molecules**: The coefficient is $1$ (implied), so the number of molecules is $1$.
- **Number of elements**: $Cr(NH_3)_6(NO_3)_3$ has four elements, chromium ($Cr$), nitrogen ($N$), hydrogen ($H$), and oxygen ($O$).
- **Number of atoms**:
    - For chromium ($Cr$): $1$ atom.
    - For nitrogen ($N$): In $(NH_3)_6$, there are $6$ $N$ atoms and in $(NO_3)_3$, there are $3$ $N$ atoms. Total $6 + 3=9$ $N$ atoms.
    - For hydrogen ($H$): In $(NH_3)_6$, $6\times3 = 18$ $H$ atoms.
    - For oxygen ($O$): In $(NO_3)_3$, $3\times3=9$ $O$ atoms.
    - Total number of atoms: $1+9 + 18+9=37$.
- **Role of $6$**: The $6$ is a subscript as it indicates the number of $NH_3$ groups in the $Cr(NH_3)_6(NO_3)_3$ molecule.

## Step4: Analyze $5Al(C_2H_3O_2)_2$
- **Number of molecules**: The coefficient $5$ indicates there are $5$ $Al(C_2H_3O_2)_2$ molecules.
- **Number of elements**: $Al(C_2H_3O_2)_2$ has four elements, aluminum ($Al$), carbon ($C$), hydrogen ($H$), and oxygen ($O$).
- **Number of atoms**:
    - For aluminum ($Al$): $5\times1 = 5$ atoms.
    - For carbon ($C$): In $(C_2H_3O_2)_2$, $2\times2=4$ $C$ atoms per formula unit. For $5$ formula units, $5\times4 = 20$ $C$ atoms.
    - For hydrogen ($H$): In $(C_2H_3O_2)_2$, $2\times3 = 6$ $H$ atoms per formula unit. For $5$ formula units, $5\times6=30$ $H$ atoms.
    - For oxygen ($O$): In $(C_2H_3O_2)_2$, $2\times2 = 4$ $O$ atoms per formula unit. For $5$ formula units, $5\times4=20$ $O$ atoms.
    - Total number of atoms: $5+20 + 30+20=75$.
- **Role of $2$**: The $2$ (in $(C_2H_3O_2)_2$) is a subscript as it indicates the number of $C_2H_3O_2$ groups in the $Al(C_2H_3O_2)_2$ molecule.

# Answer:
13)
- # of molecules: $1$
- # of elements: $2$
- Name of element: Carbon ($C$) - # of atoms: $1$; Oxygen ($O$) - # of atoms: $2$
- Total # of atoms: $3$
- The #2 is a subscript.

14)
- # of molecules: $3$
- # of elements: $2$
- Name of element: Calcium ($Ca$) - # of atoms: $3$; Chlorine ($Cl$) - # of atoms: $6$
- Total # of atoms: $9$
- The #3 is a coefficient.

15)
- # of molecules: $1$
- # of elements: $4$
- Name of element: Chromium ($Cr$) - # of atoms: $1$; Nitrogen ($N$) - # of atoms: $9$; Hydrogen ($H$) - # of atoms: $18$; Oxygen ($O$) - # of atoms: $9$
- Total # of atoms: $37$
- The #6 is a subscript.

16)
- # of molecules: $5$
- # of elements: $4$
- Name of element: Aluminum ($Al$) - # of atoms: $5$; Carbon ($C$) - # of atoms: $20$; Hydrogen ($H$) - # of atoms: $30$; Oxygen ($O$) - # of atoms: $20$
- Total # of atoms: $75$
- The #2 is a subscript.

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QUESTION IMAGE

Question

Explanation:

Step1: Analyze \(CO_2\)

Step2: Analyze \(3CaCl_2\)

Step3: Analyze \(Cr(NH_3)_6(NO_3)_3\)

Step4: Analyze \(5Al(C_2H_3O_2)_2\)

Answer: