Question

1. which of the following would behave as a strong electrolyte in water?

a. ethanol, c2h5oh
b. formaldehyde, ch2o
c. table sugar, c12h22o11
d. acetic acid, ch3cooh
e. vanadium (iii) oxide, v2o3

Explanation:

A strong electrolyte is a substance that completely dissociates into ions in water. Ethanol (\(C_2H_5OH\)) is a non - electrolyte as it does not dissociate into ions in water. Formaldehyde (\(CH_2O\)) is a non - electrolyte. Table sugar (\(C_{12}H_{22}O_{11}\)) is a non - electrolyte. Acetic acid (\(CH_3COOH\)) is a weak electrolyte as it only partially dissociates in water. Vanadium(III) oxide (\(V_2O_3\)) is an ionic compound and when it reacts with water (if it reacts in a way that allows dissociation), it can dissociate into ions. For example, if \(V_2O_3\) were to react with water (in an appropriate chemical process) to form \(V^{3 + }\) and \(O^{2-}\) (or related species in an aqueous environment), it would be a strong electrolyte.

Answer:

e. Vanadium (III) Oxide, \(V_2O_3\)