Question

1. ____ co_{2} + ____ h_{2}o \to ____ c_{2}h_{6} + ____ o_{2}

Explanation:

Step1: Balance carbon atoms

Let the coefficient of \(CO_2\) be \(x\) and of \(C_2H_6\) be \(y\). For carbon balance: \(x = 2y\). Let's first assume \(y = 2\), then \(x=4\).

Step2: Balance hydrogen atoms

Let the coefficient of \(H_2O\) be \(m\) and of \(C_2H_6\) be \(y\). For hydrogen balance: \(2m=6y\). Since \(y = 2\), then \(2m = 12\), so \(m = 6\).

Step3: Balance oxygen atoms

Let the coefficient of \(CO_2\) be \(x = 4\), of \(H_2O\) be \(m = 6\) and of \(O_2\) be \(n\). For oxygen balance: \(2x+m = 2n\). Substitute \(x = 4\) and \(m = 6\) into the equation: \(2\times4 + 6=2n\), \(8 + 6=2n\), \(14 = 2n\), so \(n = 7\).

Answer:

\(4CO_2+6H_2O
ightarrow2C_2H_6 + 7O_2\)