Question

a 4.00 l sample of a gas is at a pressure of 2.00 atm. if the temperature remains constant, what will be its volume at 0.500 atm of pressure?
8.00 l
4.00 l
16.0 l
32.0 l

Explanation:

Step1: Apply Boyle's Law

Boyle's Law: $P_1V_1 = P_2V_2$ (constant temp)
Given: $P_1=2.00$ atm, $V_1=4.00$ L, $P_2=0.500$ atm

Step2: Solve for $V_2$

Rearrange: $V_2 = \frac{P_1V_1}{P_2}$
Substitute values: $V_2 = \frac{2.00 \times 4.00}{0.500} = 16.0$ L

Answer:

16.0 L