QUESTION IMAGE
Question
which of the following could be the equation for the plane graphed above?
\\(x + y - z = 0\\)
\\(x - y + z = 0\\)
\\(-x + y + z = 0\\)
\\(x + y + z = 0\\)
🆕 New Concept Discovered: 3D Plane Visualization
Analyzing intercepts and slopes in three dimensions.
Step 1: Identify the origin and intercepts
Let's look at the center of the coordinate box where \(x = 0\) and \(y = 0\). The plane passes directly through the center of the grid, which corresponds to the origin \((0, 0, 0)\).
All four given options:
- \(x + y - z = 0\)
- \(x - y + z = 0\)
- \(-x + y + z = 0\)
- \(x + y + z = 0\)
are satisfied by the point \((0, 0, 0)\). We need to look at specific boundary points to determine the correct equation.
Step 2: Analyze boundary points from the graph
Let's observe the values of \(z\) at the corners of the domain where \(x\) and \(y\) range from \(-4\) to \(4\):
- At the far right corner:
Looking at the axes, this corresponds to \(x = -4\) (on the left-to-right axis labeled \(x\) from \(4\) to \(-4\)) and \(y = 4\) (on the back axis labeled \(y\) from \(-4\) to \(4\)).
At this corner, the plane reaches its highest point, where \(z \approx 8\) (well above \(5\)).
Let's test our options with a point like \((x, y) = (-4, 4)\) yielding a positive \(z\):
- For \(x + y - z = 0 \implies z = x + y = -4 + 4 = 0\) (Incorrect, \(z\) is clearly positive here).
- For \(x - y + z = 0 \implies z = y - x = 4 - (-4) = 8\) (Matches perfectly).
- For \(-x + y + z = 0 \implies z = x - y = -4 - 4 = -8\) (Incorrect, \(z\) is positive).
- For \(x + y + z = 0 \implies z = -x - y = -(-4) - 4 = 0\) (Incorrect).
Step 3: Verify with another corner
Let's check the front-left corner of the plane:
- This corresponds to \(x = 4\) and \(y = -4\).
- On the graph, this is the lowest point of the plane, where \(z \approx -8\) (near the bottom of the \(z\)-axis at \(-10\)).
- Let's test our matching equation \(x - y + z = 0 \implies z = y - x\):
- This perfectly matches the visual representation of the plane.
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\(x - y + z = 0\)