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when a baseball is hit by a batter, the height of the ball, \\(h(t)\\),…

Question

when a baseball is hit by a batter, the height of the ball, \\(h(t)\\), at time \\(t\\), \\(t \ge 0\\), is determined by the equation \\(h(t) = -16t^2 + 64t + 4\\). if \\(t\\) is in seconds, for which interval of time is the height of the ball greater than or equal to 52 feet?

\\(1 < t < 3\\)
\\(t \le 1\\)
\\(0 < t < 1\\)
\\(1 \le t \le 3\\)

Explanation:

Set up the quadratic inequality

$$ -16t^2 + 64t + 4 \ge 52 $$

Rearrange and simplify the inequality

$$ LATEXBLOCK0 $$

Solve the factored inequality

$$ LATEXBLOCK1 $$

Answer:

  • (A) \(1 < t < 3\)
  • (B) \(t \le 1\)
  • (C) \(0 < t < 1\)
  • (D) \(1 \le t \le 3\) (Correct answer)