QUESTION IMAGE
Question
when a baseball is hit by a batter, the height of the ball, \\(h(t)\\), at time \\(t\\), \\(t \ge 0\\), is determined by the equation \\(h(t) = -16t^2 + 64t + 4\\). if \\(t\\) is in seconds, for which interval of time is the height of the ball greater than or equal to 52 feet?
\\(1 < t < 3\\)
\\(t \le 1\\)
\\(0 < t < 1\\)
\\(1 \le t \le 3\\)
Set up the quadratic inequality
$$
-16t^2 + 64t + 4 \ge 52
$$
Rearrange and simplify the inequality
$$
LATEXBLOCK0
$$
Solve the factored inequality
$$
LATEXBLOCK1
$$
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- (A) \(1 < t < 3\)
- (B) \(t \le 1\)
- (C) \(0 < t < 1\)
- (D) \(1 \le t \le 3\) (Correct answer)