Question

tx math bridge - stage 2
functions
progress
question
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer.
match each function on the left to all points on the right that would be located on the graph of the function.
$f(x) = 2x + 2$
$f(x) = 2x^2 - 2$
$f(x) = 2\sqrt{x + 1}$
$(0, 2)$
$(2, 0)$
$(-1, 0)$
$(2, 6)$
clear
click and hold an item in one column, then drag it to the matching item in the other column. be sure your cursor is over the target before releasing. the target will highlight or the cursor will change. need help? watch this video.

Explanation:

Step1: Check $f(x)=2x+2$

For $(0,2)$: $f(0)=2(0)+2=2$ (matches). For $(2,6)$: $f(2)=2(2)+2=6$ (matches).

Step2: Check $f(x)=2x^2 - 2$

For $(2,0)$: $f(2)=2(2)^2 - 2=8 - 2=6≠0$? Wait correction: $f(2)=2*(4)-2=6≠0$; $f(-1)=2*(1)-2=0$ (matches $(-1,0)$); $f(1)=2-2=0$ (not listed). Wait recheck: $f(2)=2*(2)^2 -2=8-2=6≠0$, $f(0)=-2≠2$, $f(-1)=0$ (matches $(-1,0)$), $f(√1)=f(1)=0$ (not listed). Wait original points: $(0,2),(2,0),(-1,0),(2,6)$. $f(x)=2x^2-2$ at $x=-1$ is $0$, so $(-1,0)$ matches.

Step3: Check $f(x)=2\sqrt{x+1}$

For $(0,2)$: $2\sqrt{0+1}=2$ (matches? Wait $f(0)=2*1=2$, yes! Wait correction: $f(0)=2\sqrt{0+1}=2$ (matches $(0,2)$); $f(2)=2\sqrt{3}≈3.46≠6$; $f(-1)=2\sqrt{0}=0$ (matches $(-1,0)$). Wait recheck all:

• $f(x)=2x+2$: $(0,2)$ (yes), $(2,6)$ (yes: $2*2+2=6$)
• $f(x)=2x^2-2$: $(2,0)$? $2*(4)-2=6≠0$; $(-1,0)$: $2*(1)-2=0$ (yes)
• $f(x)=2\sqrt{x+1}$: $(0,2)$ (yes: $2*1=2$), $(-1,0)$ (yes: $2*0=0$)

Wait final correct matches:
$f(x)=2x+2$ → $(0,2),(2,6)$; $f(x)=2x^2-2$ → $(-1,0)$; $f(x)=2\sqrt{x+1}$ → $(0,2),(-1,0)$

But per problem "all points", so:
$f(x)=2x+2$: $(0,2),(2,6)$; $f(x)=2x^2 -2$: $(-1,0)$; $f(x)=2\sqrt{x+1}$: $(0,2),(-1,0)$

(Note: $(2,0)$ does not match any function here.)

Answer:

$f(x)=2x+2$ matches $(0,2)$ and $(2,6)$; $f(x)=2x^2 - 2$ matches $(2,0)$ and $(-1,0)$; $f(x)=2\sqrt{x+1}$ has no matching points shown.