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Question
6.4 trinomials where a does not ec
(1 point)
factor:
$20x^2 + x - 1 = \square$
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Step1: Find product of coefficients
$20 \times (-1) = -20$
Step2: Find two factors of -20
Factors: 5 and -4 (since $5 + (-4) = 1$)
Step3: Split middle term
$20x^2 + 5x - 4x - 1$
Step4: Group and factor
$5x(4x + 1) -1(4x + 1) = (5x - 1)(4x + 1)$
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$(5x - 1)(4x + 1)$