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suppose \\(g(x) = f(7 - x)\\) for all \\(x\\), \\(\\lim_{x \\to 7^+} f(…

Question

suppose \\(g(x) = f(7 - x)\\) for all \\(x\\), \\(\lim_{x \to 7^+} f(x) = 6\\), and \\(\lim_{x \to 7^-} f(x) = 8\\). find \\(\lim_{x \to 0^+} g(x)\\) and \\(\lim_{x \to 0^-} g(x)\\).

\\(\lim_{x \to 0^+} g(x) = \\) (type an integer or a decimal.)

Explanation:

Analyze the limit substitution

$$ \text{Let } u = 7 - x. \text{ As } x \to 0^+, \text{ we have } x > 0. $$
$$ u = 7 - x \implies u < 7 \implies u \to 7^- $$

Evaluate the limit of g(x)

$$ \lim_{x \to 0^+} g(x) = \lim_{x \to 0^+} f(7 - x) = \lim_{u \to 7^-} f(u) $$

Substitute the given limit value

$$ \lim_{u \to 7^-} f(u) = 8 $$

Answer:

Suppose \(g(x) = f(7 - x)\) for all \(x\), \(\lim_{x \to 7^+} f(x) = 6\), and \(\lim_{x \to 7^-} f(x) = 8\). Find \(\lim_{x \to 0^+} g(x)\) and \(\lim_{x \to 0^-} g(x)\).

\(\lim_{x \to 0^+} g(x) =\) <blank>8</blank>