QUESTION IMAGE
Question
solve the system by substitution.
$y = 3x - 2$
$y = 4x$
Step1: Substitute \( y = 4x \) into \( y = 3x - 2 \)
Since both equations equal \( y \), we can set them equal to each other. So substitute \( y \) in the first equation with \( 4x \) from the second equation: \( 4x = 3x - 2 \)
Step2: Solve for \( x \)
Subtract \( 3x \) from both sides: \( 4x - 3x = 3x - 2 - 3x \), which simplifies to \( x = -2 \)
Step3: Solve for \( y \)
Substitute \( x = -2 \) into \( y = 4x \): \( y = 4\times(-2) = -8 \)
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The solution to the system is \( x = -2 \), \( y = -8 \) or as an ordered pair \( (-2, -8) \)