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solve the system by substitution. $y = 3x - 2$ $y = 4x$

Question

solve the system by substitution.
$y = 3x - 2$
$y = 4x$

Explanation:

Step1: Substitute \( y = 4x \) into \( y = 3x - 2 \)

Since both equations equal \( y \), we can set them equal to each other. So substitute \( y \) in the first equation with \( 4x \) from the second equation: \( 4x = 3x - 2 \)

Step2: Solve for \( x \)

Subtract \( 3x \) from both sides: \( 4x - 3x = 3x - 2 - 3x \), which simplifies to \( x = -2 \)

Step3: Solve for \( y \)

Substitute \( x = -2 \) into \( y = 4x \): \( y = 4\times(-2) = -8 \)

Answer:

The solution to the system is \( x = -2 \), \( y = -8 \) or as an ordered pair \( (-2, -8) \)