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Question
section 03.5: problem 28
(2 points)
suppose (13,0) is a point on the graph of ( y = f(x) ). what is a point that will be on the graph of ( y=-7 f(x)+4 )?
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enter a point as ( (a, b) ), including the parentheses.
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Step1: Substitute \(x = 13\) into \(y=-7f(x)+4\)
Since \((13,0)\) is on \(y = f(x)\), then \(f(13)=0\).
Substitute \(x = 13\) into \(y=-7f(x)+4\): \(y=-7\times f(13)+4\)
Step2: Calculate the value of \(y\)
Substitute \(f(13) = 0\) into \(y=-7\times f(13)+4\)
\(y=-7\times0 + 4\)
\(y = 4\)
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\((13,4)\)