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tutorial exercise
differentiate.
f(y) = (\frac{1}{y^2} - \frac{4}{y^4})(y + 6y^3)
part 1 of 4
to find the derivative of the product f(y) = (\frac{1}{y^2} - \frac{4}{y^4})(y + 6y^3), we will use the product rule, which states
\frac{d}{dy}f(y)g(y) = f(y)g(y) + f(y)g(y).
first, we rewrite the first term of the product as follows.
\frac{1}{y^2} - \frac{4}{y^4} = y^{\square} - 4y^{\square}
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Explanation:

Step1: Rewrite first term using negative exponents

$\frac{1}{y^2} = y^{-2}$, $\frac{1}{y^4} = y^{-4}$
So $\frac{1}{y^2} - \frac{4}{y^4} = y^{-2} - 4y^{-4}$

Answer:

-2, -4