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question find the coordinates of the vertex of the following parabola algebraically. write your answer as an (x,y) point. y = 2x² - 8 answer attempt 1 out of 2 submit answer watch video show examples
Step1: Identify vertex x-coordinate
For parabola $y=ax^2+bx+c$, $x=-\frac{b}{2a}$. Here $a=2$, $b=0$.
$x=-\frac{0}{2\times2}=0$
Step2: Find vertex y-coordinate
Substitute $x=0$ into $y=2x^2-8$.
$y=2(0)^2-8=-8$
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$(0, -8)$