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Question
- (5 points) differentiate ( h(x) = sqrt{x}(x - 2) ).
Step1: Rewrite in exponential form
$h(x) = x^{1/2}(x - 2)$
Step2: Apply product rule
Let $u = x^{1/2}$, $v = x - 2$. Then $u' = \frac{1}{2}x^{-1/2}$, $v' = 1$.
Product rule: $h'(x) = u'v + uv'$
$h'(x) = \frac{1}{2}x^{-1/2}(x - 2) + x^{1/2}(1)$
Step3: Simplify the expression
$\frac{1}{2}x^{-1/2}(x - 2) = \frac{x - 2}{2\sqrt{x}} = \frac{\sqrt{x}}{2} - \frac{1}{\sqrt{x}}$
$x^{1/2} = \sqrt{x}$
Combine terms: $\frac{\sqrt{x}}{2} - \frac{1}{\sqrt{x}} + \sqrt{x} = \frac{3\sqrt{x}}{2} - \frac{1}{\sqrt{x}}$
Step4: Rewrite with common denominator (optional)
$\frac{3x - 2}{2\sqrt{x}}$
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$\frac{3\sqrt{x}}{2} - \frac{1}{\sqrt{x}}$ (or equivalent form $\frac{3x - 2}{2\sqrt{x}}$)