QUESTION IMAGE
Question
multiple choice 1 point give the exact value. sec 210° 2√3/3 -√2 -2√3/3 √2 2 multiple choice 1 point give the exact value. sec 240° -2√3/3 -2 2 2√3/3
Step1: Recall the definition of secant
$\sec\theta=\frac{1}{\cos\theta}$
Step2: Find the reference angle for \(210^{\circ}\)
The reference angle for \(210^{\circ}\) is \(210^{\circ}- 180^{\circ}=30^{\circ}\). And \(210^{\circ}\) is in the third - quadrant, where \(\cos\theta<0\). So \(\cos210^{\circ}=-\cos30^{\circ}=-\frac{\sqrt{3}}{2}\)
Step3: Calculate \(\sec210^{\circ}\)
Since \(\sec210^{\circ}=\frac{1}{\cos210^{\circ}}\), substituting \(\cos210^{\circ}=-\frac{\sqrt{3}}{2}\), we get \(\sec210^{\circ}=\frac{1}{-\frac{\sqrt{3}}{2}}=-\frac{2}{\sqrt{3}}=-\frac{2\sqrt{3}}{3}\)
Step4: Find the reference angle for \(240^{\circ}\)
The reference angle for \(240^{\circ}\) is \(240^{\circ}-180^{\circ} = 60^{\circ}\). And \(240^{\circ}\) is in the third - quadrant, where \(\cos\theta<0\). So \(\cos240^{\circ}=-\cos60^{\circ}=-\frac{1}{2}\)
Step5: Calculate \(\sec240^{\circ}\)
Since \(\sec240^{\circ}=\frac{1}{\cos240^{\circ}}\), substituting \(\cos240^{\circ}=-\frac{1}{2}\), we get \(\sec240^{\circ}=\frac{1}{-\frac{1}{2}}=- 2\)
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- \(-\frac{2\sqrt{3}}{3}\)
- \(-2\)