QUESTION IMAGE
Question
lesson 4 - 1
- if q is between a and m and mq = 7.3 and am = 8.5, then qa =?
a. 5.8 b. 1.2 c. 7.3 d. 14.6
- given: k is between h and j, hk = 2x - 5, kj = 3x + 4, and hj = 24. what is the value of x?
a. 9 b. 5 c. 19 d. 3
- if k is the mid - point of (overline{hj}), hk = x + 6, and hj = 4x - 6, then kj =?
a. 15 b. 9 c. 4 d. 10
- state the segment addition postulate in your own words.
- explain what distance along a line means as an undefined term in geometry.
Step1: Use segment - addition property
Since \(Q\) is between \(A\) and \(M\), we know that \(AM=QA + MQ\). We are given \(MQ = 7.3\) and \(AM = 8.5\). Then \(QA=AM - MQ\).
Step2: Substitute values
Substitute \(AM = 8.5\) and \(MQ = 7.3\) into the formula \(QA=AM - MQ\), we get \(QA=8.5 - 7.3=1.2\).
Step1: Apply segment - addition postulate
Since \(K\) is between \(H\) and \(J\), \(HJ=HK + KJ\). Given \(HK = 2x-5\), \(KJ = 3x + 4\), and \(HJ = 24\), we substitute these values into the equation: \(24=(2x - 5)+(3x + 4)\).
Step2: Simplify the equation
First, combine like - terms: \(24=2x-5 + 3x + 4=5x-1\).
Step3: Solve for \(x\)
Add 1 to both sides of the equation: \(24 + 1=5x\), so \(25 = 5x\). Then divide both sides by 5, \(x = 5\).
Step1: Use mid - point property
If \(K\) is the mid - point of \(\overline{HJ}\), then \(HK=KJ\) and \(HJ = 2HK\). Given \(HK=x + 6\) and \(HJ = 4x-6\), and since \(HJ = 2HK\), we have \(4x-6=2(x + 6)\).
Step2: Expand and solve for \(x\)
Expand the right - hand side: \(4x-6=2x+12\). Subtract \(2x\) from both sides: \(4x-2x-6=2x-2x + 12\), which gives \(2x-6=12\). Add 6 to both sides: \(2x=12 + 6=18\), so \(x = 9\).
Step3: Find \(KJ\)
Since \(KJ=HK=x + 6\), substitute \(x = 9\) into \(HK\), then \(KJ=9 + 6=15\).
The Segment Addition Postulate states that if we have three points \(A\), \(B\), and \(C\) that are collinear (lying on the same line) and \(B\) is between \(A\) and \(C\), then the length of segment \(AC\) is equal to the sum of the lengths of segments \(AB\) and \(BC\), i.e., \(AC=AB + BC\).
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B. 1.2