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lesson 4 - 1 1. if q is between a and m and mq = 7.3 and am = 8.5, then…

Question

lesson 4 - 1

  1. if q is between a and m and mq = 7.3 and am = 8.5, then qa =?

a. 5.8 b. 1.2 c. 7.3 d. 14.6

  1. given: k is between h and j, hk = 2x - 5, kj = 3x + 4, and hj = 24. what is the value of x?

a. 9 b. 5 c. 19 d. 3

  1. if k is the mid - point of (overline{hj}), hk = x + 6, and hj = 4x - 6, then kj =?

a. 15 b. 9 c. 4 d. 10

  1. state the segment addition postulate in your own words.
  2. explain what distance along a line means as an undefined term in geometry.

Explanation:

Step1: Use segment - addition property

Since \(Q\) is between \(A\) and \(M\), we know that \(AM=QA + MQ\). We are given \(MQ = 7.3\) and \(AM = 8.5\). Then \(QA=AM - MQ\).

Step2: Substitute values

Substitute \(AM = 8.5\) and \(MQ = 7.3\) into the formula \(QA=AM - MQ\), we get \(QA=8.5 - 7.3=1.2\).

Step1: Apply segment - addition postulate

Since \(K\) is between \(H\) and \(J\), \(HJ=HK + KJ\). Given \(HK = 2x-5\), \(KJ = 3x + 4\), and \(HJ = 24\), we substitute these values into the equation: \(24=(2x - 5)+(3x + 4)\).

Step2: Simplify the equation

First, combine like - terms: \(24=2x-5 + 3x + 4=5x-1\).

Step3: Solve for \(x\)

Add 1 to both sides of the equation: \(24 + 1=5x\), so \(25 = 5x\). Then divide both sides by 5, \(x = 5\).

Step1: Use mid - point property

If \(K\) is the mid - point of \(\overline{HJ}\), then \(HK=KJ\) and \(HJ = 2HK\). Given \(HK=x + 6\) and \(HJ = 4x-6\), and since \(HJ = 2HK\), we have \(4x-6=2(x + 6)\).

Step2: Expand and solve for \(x\)

Expand the right - hand side: \(4x-6=2x+12\). Subtract \(2x\) from both sides: \(4x-2x-6=2x-2x + 12\), which gives \(2x-6=12\). Add 6 to both sides: \(2x=12 + 6=18\), so \(x = 9\).

Step3: Find \(KJ\)

Since \(KJ=HK=x + 6\), substitute \(x = 9\) into \(HK\), then \(KJ=9 + 6=15\).

Brief Explanations

The Segment Addition Postulate states that if we have three points \(A\), \(B\), and \(C\) that are collinear (lying on the same line) and \(B\) is between \(A\) and \(C\), then the length of segment \(AC\) is equal to the sum of the lengths of segments \(AB\) and \(BC\), i.e., \(AC=AB + BC\).

Answer:

B. 1.2