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7)jasmine uses 50n of force to pull wagon of bricks 20 meters. how much…

Question

7)jasmine uses 50n of force to pull wagon of bricks 20 meters. how much work did she do?

  1. dwight uses 75n of force to move a box 15 meters. how much work did he do?
  2. how much work does an plow horse do while moving the field plow 60 meters with a pulling force of 150n?
  3. michelle does 25 joules of work to push a glass of water 2 meters. how much force did he use?
  4. sampson a basketball player does 1500 joules of work when shooting a basketball shot. the basket was 50 meters away from sampson. how much force did sampson use to shoot the shot?
  5. andre uses a force of 20 newtons to lift a sandbag while doing 40 joules of work. how far did he lift the sandbag?

Explanation:

Step1: Recall the work formula

The formula for work is \(W = F\times d\), where \(W\) is work (in joules), \(F\) is force (in newtons), and \(d\) is distance (in meters).

Step2: Solve problem 7

Given \(F = 50N\) and \(d=20m\). Substitute into the formula: \(W = 50\times20\).

$$W=1000J$$

Step3: Solve problem 8

Given \(F = 75N\) and \(d = 15m\). Substitute into the formula: \(W=75\times15\).

$$W = 1125J$$

Step4: Solve problem 9

Given \(F = 150N\) and \(d = 60m\). Substitute into the formula: \(W=150\times60\).

$$W=9000J$$

Step5: Rearrange the formula for force

From \(W = F\times d\), we can get \(F=\frac{W}{d}\).

Step6: Solve problem 10

Given \(W = 25J\) and \(d = 2m\). Substitute into \(F=\frac{W}{d}\): \(F=\frac{25}{2}\).

$$F = 12.5N$$

Step7: Solve problem 11

Given \(W = 1500J\) and \(d = 50m\). Substitute into \(F=\frac{W}{d}\): \(F=\frac{1500}{50}\).

$$F = 30N$$

Step8: Rearrange the formula for distance

From \(W = F\times d\), we can get \(d=\frac{W}{F}\).

Step9: Solve problem 12

Given \(W = 40J\) and \(F = 20N\). Substitute into \(d=\frac{W}{F}\): \(d=\frac{40}{20}\).

$$d = 2m$$

Answer:

  1. \(1000J\)
  2. \(1125J\)
  3. \(9000J\)
  4. \(12.5N\)
  5. \(30N\)
  6. \(2m\)