QUESTION IMAGE
Question
7)jasmine uses 50n of force to pull wagon of bricks 20 meters. how much work did she do?
- dwight uses 75n of force to move a box 15 meters. how much work did he do?
- how much work does an plow horse do while moving the field plow 60 meters with a pulling force of 150n?
- michelle does 25 joules of work to push a glass of water 2 meters. how much force did he use?
- sampson a basketball player does 1500 joules of work when shooting a basketball shot. the basket was 50 meters away from sampson. how much force did sampson use to shoot the shot?
- andre uses a force of 20 newtons to lift a sandbag while doing 40 joules of work. how far did he lift the sandbag?
Step1: Recall the work formula
The formula for work is \(W = F\times d\), where \(W\) is work (in joules), \(F\) is force (in newtons), and \(d\) is distance (in meters).
Step2: Solve problem 7
Given \(F = 50N\) and \(d=20m\). Substitute into the formula: \(W = 50\times20\).
Step3: Solve problem 8
Given \(F = 75N\) and \(d = 15m\). Substitute into the formula: \(W=75\times15\).
Step4: Solve problem 9
Given \(F = 150N\) and \(d = 60m\). Substitute into the formula: \(W=150\times60\).
Step5: Rearrange the formula for force
From \(W = F\times d\), we can get \(F=\frac{W}{d}\).
Step6: Solve problem 10
Given \(W = 25J\) and \(d = 2m\). Substitute into \(F=\frac{W}{d}\): \(F=\frac{25}{2}\).
Step7: Solve problem 11
Given \(W = 1500J\) and \(d = 50m\). Substitute into \(F=\frac{W}{d}\): \(F=\frac{1500}{50}\).
Step8: Rearrange the formula for distance
From \(W = F\times d\), we can get \(d=\frac{W}{F}\).
Step9: Solve problem 12
Given \(W = 40J\) and \(F = 20N\). Substitute into \(d=\frac{W}{F}\): \(d=\frac{40}{20}\).
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