Question

5.4 introduction to polynomia
(1 point)
enter \=\ if the proposed identity holds, and
\ otherwise.
$a-(x - b)square a - x - b$
$a-(x - b)square a + x + b$
$a-(x - b)square a - x + b$
note: in order to get credit for this problem all answers must be correct.
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Explanation:

Step1: Simplify \(a-(x - b)\)

Use the distributive property \(a-(x - b)=a - x + b\).

Step2: Compare with \(a - x - b\)

Since \(a - x + b
eq a - x - b\), the first one is \(N\).

Step3: Compare with \(a + x + b\)

Since \(a - x + b
eq a + x + b\), the second one is \(N\).

Step4: Compare with \(a - x + b\)

Since \(a - x + b=a - x + b\), the third one is \(=\).

Answer:

\(N\), \(N\), \(=\)