Question

graph shows how a cyclists speed changed over a 0.25 - h trip. what is the cyclists aver
2 km/h
30 km/h
20 km/h
8 km/h
part b
once the trip was started, how many times did the cyclist stop?
what was the fastest speed that the cyclist traveled? km/h

Explanation:

Step1: Recall average - speed formula

The formula for average speed is $v=\frac{d}{t}$, where $v$ is the average speed, $d$ is the total distance, and $t$ is the total time.

Step2: Determine values from the problem

From the graph, the total distance $d = 5$ km and the total time $t=0.25$ h.

Step3: Calculate average speed

Substitute $d = 5$ km and $t = 0.25$ h into the formula: $v=\frac{5}{0.25}=20$ km/h.

For the second - part:
The cyclist stops when the speed is 0. Looking at the graph, the speed is 0 two times after the trip starts.

For the third - part:
By observing the graph, the highest value on the speed - axis (vertical axis) that the curve reaches is 20 km/h.

Answer:

1. The average speed is 20 km/h.
2. The cyclist stops 2 times.
3. The fastest speed is 20 km/h.