QUESTION IMAGE
Question
the graph represents $y = \lceil x \
ceil + 1$. what is $f(-2.75)$? \ LXI0 $-5$ \ LXI1 $-4$ \ LXI2 $-2$ \ LXI3 $-1$
Step1: Recall the floor function
The function is \( y = \lfloor x
floor + 1 \), where \( \lfloor x
floor \) is the floor function, which gives the greatest integer less than or equal to \( x \).
Step2: Evaluate \( \lfloor -2.75
floor \)
For \( x = -2.75 \), the greatest integer less than or equal to \( -2.75 \) is \( -3 \) (since \( -3 \leq -2.75 < -2 \)).
Step3: Calculate \( f(-2.75) \)
Substitute \( \lfloor -2.75
floor = -3 \) into the function: \( f(-2.75) = \lfloor -2.75
floor + 1 = -3 + 1 = -2 \). Wait, no, wait. Wait, let's check again. Wait, the floor of -2.75: numbers less than or equal to -2.75. The integers are... -3, -4, etc. So the greatest integer less than or equal to -2.75 is -3? Wait, no: -3 is less than -2.75? Wait, -3 is less than -2.75? Wait, -3 is more negative, so -3 < -2.75 < -2. So the greatest integer less than or equal to -2.75 is -3? Wait, no, wait: -3 is less than -2.75, -2 is greater than -2.75. So the greatest integer less than or equal to -2.75 is -3? Wait, no, that's wrong. Wait, the floor function: for a negative number, it's the next lower integer. So for -2.75, the floor is -3? Wait, no, let's take an example: floor(-2.1) is -3? No, floor(-2.1) is -3? Wait, no, floor(-2.1) is -3? Wait, no, -3 is less than -2.1, -2 is greater than -2.1. So the greatest integer less than or equal to -2.1 is -3? Wait, no, that's incorrect. Wait, no: the floor of a number is the greatest integer less than or equal to that number. So for -2.75, the integers less than or equal to -2.75 are..., -4, -3, -2.75 is between -3 and -2. So the greatest integer less than or equal to -2.75 is -3? Wait, no, -3 is less than -2.75, -2 is greater than -2.75. So the greatest integer less than or equal to -2.75 is -3? Wait, no, that's not right. Wait, let's check with a calculator: floor(-2.75) is -3? Wait, no, actually, floor(-2.75) is -3? Wait, no, I think I made a mistake. Wait, no: -2.75 is between -3 and -2. The greatest integer less than or equal to -2.75 is -3? Wait, no, -3 is less than -2.75, -2 is greater than -2.75. So the greatest integer less than or equal to -2.75 is -3? Wait, that can't be. Wait, no, the floor of -2.75 is -3? Wait, no, let's think again. Let's take x = -2.75. The floor function gives the largest integer less than or equal to x. So integers less than or equal to -2.75: -3, -4, -5, etc. The largest among these is -3? Wait, no, -3 is larger than -4, -5, etc. So yes, the largest integer less than or equal to -2.75 is -3. So then f(-2.75) = -3 + 1 = -2? But wait, looking at the graph, let's check the graph. The graph for x between -3 and -2 (not including -2), what's the y-value? Looking at the graph, when x is between -3 and -2 (like -2.75), the blue dot (the closed circle) is at y = -2? Wait, no, the graph: let's see the points. At x between -3 and -2 (the interval [-3, -2)), the y-value: looking at the graph, there's a segment with a closed circle at x=-3? Wait, no, the graph has a segment where x is between -3 and -2 (maybe), with y=-2? Wait, the graph shows that for x in [-3, -2), the y is -2? Wait, no, let's look at the graph. The leftmost blue dot is at x=-5, y=-4? Then a segment from x=-5 to x=-4 (open at -4) with y=-3? Then x=-4 to x=-3 (open at -3) with y=-2? Then x=-3 to x=-2 (open at -2) with y=-1? Wait, no, the graph: the point at x=-3 (open circle?) and closed circle at x=-2? Wait, no, the graph has a closed circle at x=-2 (y=-1?) Wait, maybe I messed up the floor function. Wait, the function is \( y = \lfloor x
floor + 1 \). So let's re-express:
For x in [n, n+1), where n is an integer, \…
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