Question

graph this line using the slope
y = -8x + 1
click to select points on the gr

Explanation:

Step1: Identify slope and intercept

The equation is in slope - intercept form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. For \(y=-8x + 1\), the slope \(m=-8=\frac{-8}{1}\) and the y - intercept \(b = 1\). So the line crosses the y - axis at \((0,1)\).

Step2: Use slope to find another point

The slope is \(\frac{\text{rise}}{\text{run}}=\frac{-8}{1}\). Starting from the y - intercept \((0,1)\), we move down 8 units (because the rise is - 8) and 1 unit to the right (because the run is 1). So we get the point \((0 + 1,1-8)=(1,-7)\). We can also move up 8 units and 1 unit to the left: \((0 - 1,1 + 8)=(-1,9)\).

Step3: Plot the points and draw the line

Plot the points \((0,1)\) and \((1,-7)\) (or \((-1,9)\)) on the coordinate plane and then draw a straight line through them.

Answer:

To graph \(y = - 8x+1\), plot the y - intercept \((0,1)\) and use the slope \(-8\) to find another point (e.g., \((1, - 7)\) or \((-1,9)\)) and draw a line through these points.