Question

graph the inverse of the provided graph on the accompanying set of axes. you must plot at least 5 points. click the graph to make a point. click it again to erase.

Explanation:

Step1: Identify Original Points

First, find at least 5 points on the original line. Let's assume the original line has points like \((0, -2)\), \((1, 0)\), \((2, 2)\), \((3, 4)\), \((4, 6)\) (by observing the slope, which seems to be 2, so \(y = 2x - 2\)).

Step2: Find Inverse Points

To find the inverse of a point \((x, y)\), we swap \(x\) and \(y\). So for each original point:

• For \((0, -2)\), inverse is \((-2, 0)\)
• For \((1, 0)\), inverse is \((0, 1)\)
• For \((2, 2)\), inverse is \((2, 2)\) (since swapping \(x\) and \(y\) gives the same point)
• For \((3, 4)\), inverse is \((4, 3)\)
• For \((4, 6)\), inverse is \((6, 4)\)

Step3: Plot Inverse Points

Now, plot these inverse points \((-2, 0)\), \((0, 1)\), \((2, 2)\), \((4, 3)\), \((6, 4)\) on the same set of axes. The line through these points will be the graph of the inverse function. The inverse of a linear function \(y = mx + b\) (where \(m
eq0\)) is also a linear function, and since the original line has a slope of 2, the inverse will have a slope of \(\frac{1}{2}\) (though plotting points is more straightforward here).

Answer:

To graph the inverse, swap the \(x\)- and \(y\)-coordinates of at least 5 points on the original line (e.g., \((0, -2)\to(-2, 0)\), \((1, 0)\to(0, 1)\), \((2, 2)\to(2, 2)\), \((3, 4)\to(4, 3)\), \((4, 6)\to(6, 4)\)) and plot them, then draw the line through these inverse points. The final graph of the inverse will be a line passing through these swapped points.