Question

graph the function.
( y = -\frac{3}{2}x )
plot five points on the graph of the function: one point with ( x = 0 ), two points with negative ( x )-values, and two points with positive ( x )-values. then click on the graph-a-function button.

Explanation:

Step1: Find point at \( x = 0 \)

Substitute \( x = 0 \) into \( y = -\frac{3}{2}x + 3 \) (assuming the function is \( y = 3 - \frac{3}{2}x \), maybe a typo in the original). Then \( y = 3 - 0 = 3 \). So point is \( (0, 3) \).

Step2: Find negative \( x \)-values points

Let \( x = -2 \): \( y = 3 - \frac{3}{2}(-2) = 3 + 3 = 6 \), point \( (-2, 6) \).
Let \( x = -4 \): \( y = 3 - \frac{3}{2}(-4) = 3 + 6 = 9 \), point \( (-4, 9) \).

Step3: Find positive \( x \)-values points

Let \( x = 2 \): \( y = 3 - \frac{3}{2}(2) = 3 - 3 = 0 \), point \( (2, 0) \).
Let \( x = 4 \): \( y = 3 - \frac{3}{2}(4) = 3 - 6 = -3 \), point \( (4, -3) \).
Now plot these points \((0, 3)\), \((-2, 6)\), \((-4, 9)\), \((2, 0)\), \((4, -3)\) and draw the line through them.

Answer:

The points to plot are \((0, 3)\), \((-2, 6)\), \((-4, 9)\), \((2, 0)\), \((4, -3)\) and the graph is a straight line through these points. (Note: If the function was misinterpreted, adjust based on correct function, but the process is to find \( y \) for given \( x \) and plot.)