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2) given $f(x) = 2x^2 + 3x - 5$ evaluate when $x = 4$

Question

  1. given

$f(x) = 2x^2 + 3x - 5$
evaluate when $x = 4$

Explanation:

Step1: Substitute x = 4 into the function

Substitute \( x = 4 \) into \( f(x) = 2x^2 + 3x - 5 \), we get \( f(4) = 2(4)^2 + 3(4) - 5 \).

Step2: Calculate the exponent

First, calculate \( (4)^2 = 16 \), so the expression becomes \( f(4) = 2\times16 + 3\times4 - 5 \).

Step3: Perform multiplication operations

Calculate \( 2\times16 = 32 \) and \( 3\times4 = 12 \), then the expression is \( f(4) = 32 + 12 - 5 \).

Step4: Perform addition and subtraction

First, \( 32 + 12 = 44 \), then \( 44 - 5 = 39 \).

Answer:

39