Question

the function f(x) is graphed below. enter the y-intercept as an ordered pair.
f(x) = -2|x + 2| + 4
draw

Explanation:

Step1: Recall y-intercept definition

The y-intercept occurs where \( x = 0 \). So we substitute \( x = 0 \) into the function \( f(x)=-2|x + 2|+4 \).

Step2: Substitute and simplify

Substitute \( x = 0 \):
\( f(0)=-2|0 + 2|+4 \)
First, calculate the absolute value: \( |0 + 2|=|2| = 2 \).
Then, multiply: \( -2\times2=-4 \).
Finally, add: \( -4 + 4 = 0 \).
So when \( x = 0 \), \( f(0)=0 \), which means the y-intercept is at the point \( (0, 0) \).

Answer:

\((0, 0)\)