Question

for the function $f(x) = 2^{-x}$ calculate the following function values:
$f(1) = $
$f(2) = $

Explanation:

Step1: Calculate \( f(1) \)

Substitute \( x = 1 \) into \( f(x)=2^{-x} \). Using the exponent rule \( a^{-n}=\frac{1}{a^n} \), we get \( f(1)=2^{-1}=\frac{1}{2^1}=\frac{1}{2} \).

Step2: Calculate \( f(2) \)

Substitute \( x = 2 \) into \( f(x)=2^{-x} \). Using the exponent rule \( a^{-n}=\frac{1}{a^n} \), we get \( f(2)=2^{-2}=\frac{1}{2^2}=\frac{1}{4} \).

Answer:

\( f(1) = \frac{1}{2} \)
\( f(2) = \frac{1}{4} \)