Question

in the following exercise, find the coordinates of the vertex for the parabola defined by the given quadratic function.
$f(x)=4(x - 8)^2 + 1$
the vertex is \boxed{}. (type an ordered pair.)

Explanation:

Step1: Recall vertex form of parabola

The vertex form of a quadratic function is \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

Step2: Identify h and k from given function

Given the function \( f(x) = 4(x - 8)^2 + 1 \), we compare it with the vertex form. Here, \( h = 8 \) and \( k = 1 \).

Answer:

\((8, 1)\)