find an ordered pair $(x, y)$ that is a solution to the equation.

\4x + y = 5\

$(x, y) = (\square, \square)$

Question

find an ordered pair $(x, y)$ that is a solution to the equation.

\4x + y = 5\

$(x, y) = (\square, \square)$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [], "new_concepts": [ "Linear Equation Solutions", "Ordered Pairs" ], "current_concepts": [ "Linear Equation Solutions", "Ordered Pairs" ] } ## Choose an arbitrary value for x $$ x = 1 $$ ## Substitute x into the equation and solve for y $$ \begin{aligned} 4(1) + y &= 5 \ 4 + y &= 5 \ y &= 1 \end{aligned} $$ ## Form the ordered pair $$ (x, y) = (1, 1) $$ Find an ordered pair $(x, y)$ that is a solution to the equation. $4x + y = 5$ $(x, y) =$ $(1, 1)$ { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Linear Equation Solutions" ] }

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QUESTION IMAGE

Question

Explanation:

Choose an arbitrary value for x

Substitute x into the equation and solve for y

Form the ordered pair

Answer: