Question

find an ordered pair \\((x, y)\\) that is a solution to the equation.

\\4x + y = 5\\

\\((x, y) = (\square, \square)\\)

Explanation:

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<reasoning>

Choose an arbitrary value for x

\[
x = 1
\]

Substitute x into the equation and solve for y

\[

$$\begin{aligned} 4(1) + y &= 5 \\ 4 + y &= 5 \\ y &= 1 \end{aligned}$$

\]

Form the ordered pair

\[
(x, y) = (1, 1)
\]
</reasoning>

<answer>
Find an ordered pair \((x, y)\) that is a solution to the equation.

\(4x + y = 5\)

\((x, y) =\) <blank>\((1, 1)\)</blank>
</answer>

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"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Linear Equation Solutions"
]
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Answer:

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</pre_analysis>

<reasoning>

Choose an arbitrary value for x

\[
x = 1
\]

Substitute x into the equation and solve for y

\[

$$\begin{aligned} 4(1) + y &= 5 \\ 4 + y &= 5 \\ y &= 1 \end{aligned}$$

\]

Form the ordered pair

\[
(x, y) = (1, 1)
\]
</reasoning>

<answer>
Find an ordered pair \((x, y)\) that is a solution to the equation.

\(4x + y = 5\)

\((x, y) =\) <blank>\((1, 1)\)</blank>
</answer>

<post_analysis>
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"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Linear Equation Solutions"
]
}
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