Question

find the indicated value of ( f(x,y,z)=4x + 3y^{5}-9z^{3}-6 ).
( f(0,0,0) )
( f(0,0,0)=square )
(simplify your answer.)

Explanation:

Step1: Substitute \(x = 0\), \(y = 0\), \(z = 0\) into the function

Given \(f(x,y,z)=4x + 3y^{5}-9z^{3}-6\), substitute \(x = 0\), \(y = 0\), \(z = 0\).
We get \(f(0,0,0)=4\times0+3\times0^{5}-9\times0^{3}-6\).

Step2: Simplify the expression

Calculate each term:

• \(4\times0 = 0\)
• \(3\times0^{5}=3\times0 = 0\)
• \(9\times0^{3}=9\times0 = 0\)

So \(f(0,0,0)=0 + 0-0 - 6\).

Answer:

\(-6\)