Question

find the domain of the function. v (x)=√x +2 write your answer as an inequality. or, you may instead click on \empty set\ or \all reals\ as the answer.

Explanation:

Step1: Recall domain of square root

The square root function $\sqrt{x}$ is defined when the radicand $x$ is non - negative (i.e., $x\geq0$), because we can't take the square root of a negative number in the set of real numbers.

Step2: Determine domain of \(v(x)\)

For the function \(v(x)=\sqrt{x} + 2\), the only restriction comes from the square root part \(\sqrt{x}\). So the domain of \(v(x)\) is the set of all real numbers \(x\) such that \(x\geq0\).

Answer:

\(x\geq0\)