QUESTION IMAGE
Question
exercise 1
a. write the following mathematical expressions or equations into verbal statements
- \\( \lim _ { x \
ightarrow - 2 ^ { - } } \left( 2 x ^ { 2 } \
ight) \\)
- \\( \lim _ { x \
ightarrow 1 } \left( x ^ { 2 } - 2 x + 1 \
ight) = 0 \\)
- \\( \lim _ { x \
ightarrow 1 ^ { + } } \left( 5 x ^ { 2 } - 1 \
ight) \\)
- \\( \lim _ { x \
ightarrow - 3 } \left( \frac { 2 x ^ { 2 } } { x + 1 } \
ight) = - 4 \\)
b. write the following verbal statements into mathematical expressions or equations
- the limit of the sum of one and thrice of \\( x \\) as \\( x \\) approaches 2
- the limit of absolute value of \\( x \\) as \\( x \\) approaches to 0
- the limit of the quotient of \\( x \\) equaled minus 9 and \\( x \\) minus 3 as \\( x \\) approaches 3 is equal to 6
- the limit of the square root of \\( x \\) minus 3 as \\( x \\) approaches 7 equals 2
exercise 2
Step1: Translate mathematical expressions to verbal statements
For \( \lim_{x
ightarrow - 2}(2x^{2})\)
The limit of \(2x^{2}\) as \(x\) approaches \(-2\)
For \( \lim_{x
ightarrow +\infty}(5x^{2}-1)\)
The limit of \(5x^{2}-1\) as \(x\) approaches positive infinity
For \( \lim_{x
ightarrow 1}(x^{2}-2x + 1)=0\)
The limit of \(x^{2}-2x + 1\) as \(x\) approaches \(1\) is equal to \(0\)
For \( \lim_{x
ightarrow - 3}(\frac{2x + 6}{x+3})=-4\)
The limit of \(\frac{2x + 6}{x + 3}\) as \(x\) approaches \(-3\) is equal to \(-4\)
Step2: Translate verbal statements to mathematical expressions
For "The limit of sum of one and thrice of \(x\) as \(x\) approaches \(2\)"
\(\lim_{x
ightarrow 2}(1 + 3x)\)
For "The limit of absolute value of \(x\) as \(x\) approaches \(0\)"
\(\lim_{x
ightarrow 0}|x|\)
For "The limit of the quotient of \(x\) squared minus \(9\) and \(x\) minus \(3\) as \(x\) approaches \(3\) is equal to \(6\)"
\(\lim_{x
ightarrow 3}\frac{x^{2}-9}{x - 3}=6\)
For "The limit of the square root of \(x\) minus \(3\) as \(x\) approaches \(7\) equals \(2\)"
\(\lim_{x
ightarrow 7}(\sqrt{x}-3)=2\)
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- The limit of \(2x^{2}\) as \(x\) approaches \(-2\)
- The limit of \(5x^{2}-1\) as \(x\) approaches positive infinity
- The limit of \(x^{2}-2x + 1\) as \(x\) approaches \(1\) is equal to \(0\)
- The limit of \(\frac{2x + 6}{x + 3}\) as \(x\) approaches \(-3\) is equal to \(-4\)
- \(\lim_{x
ightarrow 2}(1 + 3x)\)
- \(\lim_{x
ightarrow 0}|x|\)
- \(\lim_{x
ightarrow 3}\frac{x^{2}-9}{x - 3}=6\)
- \(\lim_{x
ightarrow 7}(\sqrt{x}-3)=2\)