QUESTION IMAGE
Question
drag and drop the descriptions in the box that
correctly classifies the angle pairs
you may use multiple responses in the boxes.
\\( \angle a o b \\) and \\( \angle b o c \\) \\( \angle a o c \\) and \\( \angle c o d \\)
adjacent complementary
supplementary vertical
Step1: Recall the definitions
- Adjacent angles: share a common vertex and a common side, and no common interior points.
- Complementary angles: sum to \(90^{\circ}\).
- Supplementary angles: sum to \(180^{\circ}\).
- Vertical angles: opposite angles formed by two intersecting lines.
Step2: Analyze \(\angle AOB\) and \(\angle BOC\)
- They share vertex \(O\) and side \(OB\), so they are adjacent.
- \(\angle AOB = 90^{\circ}\), and \(\angle AOB+\angle BOC=\angle AOC\). Since \(\angle AOC\) is not \(90^{\circ}\) (from the figure), they are not complementary.
- \(\angle AOB+\angle BOC
eq180^{\circ}\) (as \(\angle AOB = 90^{\circ}\) and \(\angle BOC\) is acute), so not supplementary.
- Not vertical (not opposite by two - line intersection).
Step3: Analyze \(\angle AOC\) and \(\angle COD\)
- They share vertex \(O\) and side \(OC\), so adjacent.
- \(\angle AOC+\angle COD=\angle AOD = 180^{\circ}\) (since \(AOD\) is a straight line), so supplementary.
- \(\angle AOC+\angle COD
eq90^{\circ}\), not complementary.
- Not vertical (not opposite by two - line intersection).
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\(\angle AOB\) and \(\angle BOC\): adjacent; \(\angle AOC\) and \(\angle COD\): adjacent, supplementary