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drag and drop the descriptions in the box that correctly classifies the…

Question

drag and drop the descriptions in the box that
correctly classifies the angle pairs
you may use multiple responses in the boxes.
\\( \angle a o b \\) and \\( \angle b o c \\) \\( \angle a o c \\) and \\( \angle c o d \\)
adjacent complementary
supplementary vertical

Explanation:

Step1: Recall the definitions

  • Adjacent angles: share a common vertex and a common side, and no common interior points.
  • Complementary angles: sum to \(90^{\circ}\).
  • Supplementary angles: sum to \(180^{\circ}\).
  • Vertical angles: opposite angles formed by two intersecting lines.

Step2: Analyze \(\angle AOB\) and \(\angle BOC\)

  • They share vertex \(O\) and side \(OB\), so they are adjacent.
  • \(\angle AOB = 90^{\circ}\), and \(\angle AOB+\angle BOC=\angle AOC\). Since \(\angle AOC\) is not \(90^{\circ}\) (from the figure), they are not complementary.
  • \(\angle AOB+\angle BOC

eq180^{\circ}\) (as \(\angle AOB = 90^{\circ}\) and \(\angle BOC\) is acute), so not supplementary.

  • Not vertical (not opposite by two - line intersection).

Step3: Analyze \(\angle AOC\) and \(\angle COD\)

  • They share vertex \(O\) and side \(OC\), so adjacent.
  • \(\angle AOC+\angle COD=\angle AOD = 180^{\circ}\) (since \(AOD\) is a straight line), so supplementary.
  • \(\angle AOC+\angle COD

eq90^{\circ}\), not complementary.

  • Not vertical (not opposite by two - line intersection).

Answer:

\(\angle AOB\) and \(\angle BOC\): adjacent; \(\angle AOC\) and \(\angle COD\): adjacent, supplementary