QUESTION IMAGE
Question
g cr sem a aguirre
of exponential functions
horizontal translations
graph: $f(x) = 2^{x - 1}$
step 1: find the value of $x$ that makes the exponent zero by solving this equation: $x - 1 = 0$
$x = 1$
calculate the value of the function.
$f(1) = 1$
step 2: plot the value of the function at $(1, 1)$.
step 3: evaluate the function at two more points.
$f(0) = 1/2$ $f(2) = $
(options for $f(2)$: 1/2, 1, 2)
(graph with grid, y-axis labeled y, x-axis labeled x, point (1,1) plotted, table with x=1, y=1)
Step1: Evaluate \( f(2) \)
Substitute \( x = 2 \) into \( f(x)=2^{x - 1} \). So \( f(2)=2^{2 - 1}=2^{1}=2 \).
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