Question

1. given f(x) = -8x + 2 has a domain of {-4, -2, 0, 2, 4}. what is the range? type a response a.7.e ← previous

Explanation:

Step1: Substitute \( x = -4 \) into \( f(x) \)

\( f(-4) = -8\times(-4) + 2 = 32 + 2 = 34 \)

Step2: Substitute \( x = -2 \) into \( f(x) \)

\( f(-2) = -8\times(-2) + 2 = 16 + 2 = 18 \)

Step3: Substitute \( x = 0 \) into \( f(x) \)

\( f(0) = -8\times0 + 2 = 0 + 2 = 2 \)

Step4: Substitute \( x = 2 \) into \( f(x) \)

\( f(2) = -8\times2 + 2 = -16 + 2 = -14 \)

Step5: Substitute \( x = 4 \) into \( f(x) \)

\( f(4) = -8\times4 + 2 = -32 + 2 = -30 \)

Answer:

The range is \(\{34, 18, 2, -14, -30\}\)