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Question
- the minimum fine for driving in excess of the speed limit is $25. an additional $6 is added to the minimum fine for each mile per hour (mph) in excess of the speed limit. rachel was issued a $103 fine for speeding in a 55 - mph speed limit zone. for driving at what speed, in mph, was rachel fined?
a. 48
b. 52
c. 62
d. 68
e. 78
- the expression $5x^{3}×2xy×3xy^{2}$ is equivalent to:
a. $10x^{3}y^{2}$
b. $10x^{6}y^{3}$
c. $30x^{3}y^{3}$
d. $30x^{6}y^{3}$
e. $30x^{6}y^{2}$
Question 16
Step1: Find the amount due to excess speed
The total fine is $103$ and the minimum fine is $25$. So the amount due to excess speed is \(103 - 25=78\) dollars.
Step2: Find the number of miles over the speed limit
Since each mile over the speed limit adds $6$ dollars, the number of miles over the speed limit \(n=\frac{78}{6} = 13\) mph.
Step3: Find Rachel's speed
The speed limit is $55$ mph. So Rachel's speed \(v=55 + 13=68\) mph.
Step1: Multiply the coefficients
Multiply the coefficients \(5\times2\times3 = 30\).
Step2: Use the rule of exponents for \(x\)
For \(x\) terms: \(x^{3}\times x\times x=x^{3 + 1+1}=x^{5}\) (using \(a^{m}\times a^{n}=a^{m + n}\)).
Step3: Use the rule of exponents for \(y\)
For \(y\) terms: \(y\times y^{2}=y^{1+2}=y^{3}\) (using \(a^{m}\times a^{n}=a^{m + n}\)).
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D. 68