write the formula for copper(ii) sulfate. *
your answer
name the compound k₂mno₄. *
your answer
balance the following equation: *
al + fe₂o₃ → fe + al₂o₃
your answer
balance the following equation: *
c₄h₁₀ + o₂ → co₂ + h₂o
your answer
balance the following equation: *
na₃po₄ + cacl₂ → ca₃(po₄)₂ + nacl

Question

Accepted Answer

# Explanation:
## Step1: Write the formula for copper(II) sulfate
Copper(II) has a charge of $Cu^{2+}$, sulfate has a charge of $SO_{4}^{2 -}$. Using the criss - cross method (since the charges are equal in magnitude), the formula is $CuSO_{4}$.
## Step2: Name the compound $K_{2}MnO_{4}$
$K$ is potassium. The polyatomic ion $MnO_{4}^{2-}$ is manganate. So the name is potassium manganate.
## Step3: Balance $Al + Fe_{2}O_{3}\to Fe + Al_{2}O_{3}$
- For $Al$: Let the coefficient of $Al$ be $2$ (to balance $Al$ on the right - hand side where there are $2$ $Al$ atoms in $Al_{2}O_{3}$).
- For $Fe$: There are $2$ $Fe$ atoms in $Fe_{2}O_{3}$, so the coefficient of $Fe$ is $2$. The balanced equation is $2Al+Fe_{2}O_{3}\to 2Fe + Al_{2}O_{3}$
## Step4: Balance $C_{4}H_{10}+O_{2}\to CO_{2}+H_{2}O$
- Balance $C$: Let the coefficient of $CO_{2}$ be $4$ (since there are $4$ $C$ atoms in $C_{4}H_{10}$).
- Balance $H$: There are $10$ $H$ atoms in $C_{4}H_{10}$, so the coefficient of $H_{2}O$ is $5$.
- Balance $O$: On the right - hand side, there are $4\times2 + 5\times1=13$ $O$ atoms. So the coefficient of $O_{2}$ is $\frac{13}{2}$. Multiply all coefficients by $2$ to get whole numbers. The balanced equation is $2C_{4}H_{10}+13O_{2}\to 8CO_{2}+10H_{2}O$
## Step5: Balance $Na_{3}PO_{4}+CaCl_{2}\to Ca_{3}(PO_{4})_{2}+NaCl$
- Balance $Ca$: Let the coefficient of $CaCl_{2}$ be $3$ (to balance $3$ $Ca$ atoms in $Ca_{3}(PO_{4})_{2}$).
- Balance $PO_{4}$: Let the coefficient of $Na_{3}PO_{4}$ be $2$ (to balance $2$ $PO_{4}$ groups in $Ca_{3}(PO_{4})_{2}$).
- Balance $Na$ and $Cl$: The coefficient of $NaCl$ is $6$. The balanced equation is $2Na_{3}PO_{4}+3CaCl_{2}\to Ca_{3}(PO_{4})_{2}+6NaCl$

# Answer:
1. $CuSO_{4}$
2. Potassium manganate
3. $2Al + Fe_{2}O_{3}\to 2Fe+Al_{2}O_{3}$
4. $2C_{4}H_{10}+13O_{2}\to 8CO_{2}+10H_{2}O$
5. $2Na_{3}PO_{4}+3CaCl_{2}\to Ca_{3}(PO_{4})_{2}+6NaCl$

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QUESTION IMAGE

Question

Explanation:

Step1: Write the formula for copper(II) sulfate

Step2: Name the compound \(K_{2}MnO_{4}\)

Step3: Balance \(Al + Fe_{2}O_{3}\to Fe + Al_{2}O_{3}\)

Step4: Balance \(C_{4}H_{10}+O_{2}\to CO_{2}+H_{2}O\)

Step5: Balance \(Na_{3}PO_{4}+CaCl_{2}\to Ca_{3}(PO_{4})_{2}+NaCl\)

Answer: