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classify each of these compounds as ionic or covalent:
nabr
sf₄
cubr₂
of₂
no₂
bas
csf₂
crcl₃
co₂
co

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# Brief Explanations:
- **Ionic compounds**: Generally formed between metals and non - metals. The metal donates electrons to the non - metal, creating ions that are held together by electrostatic forces.
    - For $NaBr$: Sodium ($Na$) is a metal and bromine ($Br$) is a non - metal.
    - For $BaS$: Barium ($Ba$) is a metal and sulfur ($S$) is a non - metal.
    - For $CaBr_{2}$: Calcium ($Ca$) is a metal and bromine ($Br$) is a non - metal.
    - For $CsF_{2}$: Cesium ($Cs$) is a metal and fluorine ($F$) is a non - metal.
- **Covalent compounds**: Formed between non - metals. Atoms share electrons to achieve a stable electron configuration.
    - For $SF_{4}$: Both sulfur ($S$) and fluorine ($F$) are non - metals.
    - For $OF_{2}$: Oxygen ($O$) and fluorine ($F$) are non - metals.
    - For $NO_{2}$: Nitrogen ($N$) and oxygen ($O$) are non - metals.
    - For $CrCl_{3}$: Chromium ($Cr$) is a transition metal, but in $CrCl_{3}$, the bonding is more covalent in nature (due to the relatively high charge density of $Cr^{3 +}$ and the tendency of $Cl^{-}$ to polarize and form more covalent character).
    - For $CO_{2}$: Carbon ($C$) and oxygen ($O$) are non - metals.
    - For $CO$: Carbon ($C$) and oxygen ($O$) are non - metals.

# Answer:
- $NaBr$: Ionic
- $BaS$: Ionic
- $SF_{4}$: Covalent
- $CsF_{2}$: Ionic
- $CaBr_{2}$: Ionic
- $CrCl_{3}$: Covalent
- $OF_{2}$: Covalent
- $CO_{2}$: Covalent
- $NO_{2}$: Covalent
- $CO$: Covalent

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