Question

a zookeeper records the number and types of primates housed in a single exhibit.
the table shows the count for one day.

part a - the zookeeper incorrectly says that the percent of marmoset is equivalent to \\( \frac { 3 } { 32 } \\). explain her likely error.

part b - what percent of primates were capuchin monkeys? round to the nearest whole percent.

Explanation:

Step1: Calculate total number of primates

Total number of primates \(=8 + 24+3=35\)

Step2: Analyze Part A

The zookeeper likely used \(8 + 24=32\) (sum of ring - tailed lemur and capuchin monkey counts) as the denominator instead of the total number of primates (\(35\)). The correct fraction for marmoset is \(\frac{3}{35}\)

Step3: Calculate percentage for Part B

Percentage of capuchin monkeys \(=\frac{24}{35}\times100\)

$$
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$$

Rounding to the nearest whole percent gives \(69\%\)

Answer:

Part A: The zookeeper used \(32\) (sum of ring - tailed lemur and capuchin monkey counts) as the denominator instead of \(35\) (total number of primates). Part B: \(69\%\)