Question

you know the \q\ because it was calculated to be 1,030.38 j. you know the change in temperature (delta t) of a reaction to be 26.8 c. the mass of the heated object is 52.3 g. calculate the specific heat of the object that was heated.

Explanation:

Step1: Recall the specific heat formula

The formula for heat \( q = mc\Delta T\), where \(q\) is the heat energy, \(m\) is the mass, \(c\) is the specific heat, and \(\Delta T\) is the change in temperature. We need to solve for \(c\), so \(c=\frac{q}{m\Delta T}\).

Step2: Substitute the given values

Given \(q = 1030.38\space J\), \(m = 52.3\space g\), and \(\Delta T=26.8^{\circ}C\).
Substitute into the formula: \(c=\frac{1030.38}{52.3\times26.8}\).
First, calculate \(52.3\times26.8 = 1401.64\).
Then, \(c=\frac{1030.38}{1401.64}\).

Step3: Calculate the value of \(c\)

\(c = 0.735\space J/(g\cdot^{\circ}C)\)

Answer:

\(0.735\space J/(g\cdot^{\circ}C)\)