Question

y = -x² - 4x + 1; x = -2; - ( )² - 4( ) + 1

Explanation:

Step1: Substitute \( x = -2 \)

We substitute \( x = -2 \) into the expression \( -x^2 - 4x + 1 \). So we replace each \( x \) with \( -2 \), getting \( -(-2)^2 - 4(-2) + 1 \).

Step2: Calculate each term

First, calculate \( (-2)^2 = 4 \), so \( -(-2)^2 = -4 \). Then, \( -4(-2) = 8 \). Now we have \( -4 + 8 + 1 \).

Step3: Sum the terms

\( -4 + 8 = 4 \), and \( 4 + 1 = 5 \).

Answer:

When \( x = -2 \), the value of \( y = -x^2 - 4x + 1 \) is \( 5 \), and the filled - in expression is \( -(-2)^2 - 4(-2)+1 \).