Question

write the products of the acid hydrolysis of the ester with the formula $ch_{3}cooch(ch_{3})_{2}$.

• use chemical symbols.
• for the first product fill in the remaining part of the acid formula.
• for the second product fill in the whole formula for the alcohol.

provide your answer below:
$ch_{3}cooch(ch_{3})_{2}+h_{2}ooverset{h^{+}}{
ightleftharpoons}square cooh+square$

Explanation:

Step1: Analyze the ester structure

The ester is $CH_3COOCH(CH_3)_2$. In acid - catalyzed hydrolysis of an ester ($R - COOR'$), the general reaction is $R - COOR'+H_2O\stackrel{H^+}{
ightleftharpoons}R - COOH + R'OH$.
For the given ester $CH_3COOCH(CH_3)_2$, the acyl part ($R - CO -$) is $CH_3CO -$ and the alkyl part ($-OR'$) is $-OCH(CH_3)_2$.

Step2: Write the products

When hydrolyzed, the acyl part combines with $-OH$ from water to form the carboxylic acid. The $CH_3CO -$ part combines with $-OH$ to give $CH_3COOH$.
The $-OCH(CH_3)_2$ part combines with $-H$ from water. The $-OCH(CH_3)_2$ group, when combined with $-H$, gives the alcohol $(CH_3)_2CHOH$.

Answer:

$CH_3COOH + (CH_3)_2CHOH$