QUESTION IMAGE
Question
write an orbital diagram for argon.
drag the appropriate labels to their respective targets. labels can be used once, more than once, or not at all.
ar
1s 2s 2p 3s 3p
Step1: Determine Argon's Electron Configuration
Argon (Ar) has an atomic number of 18, so its electron configuration is \(1s^2 2s^2 2p^6 3s^2 3p^6\). This means each orbital is filled with two electrons (represented by the label "11" for paired electrons, or "1" for unpaired, but in argon all orbitals are fully paired here).
Step2: Fill Each Orbital
- \(1s\) orbital: Holds 2 electrons, so place "11" in the \(1s\) box.
- \(2s\) orbital: Holds 2 electrons, place "11" in the \(2s\) box.
- \(2p\) orbitals (three orbitals): Each \(2p\) orbital holds 2 electrons, so each of the three \(2p\) boxes gets "11" (since \(2p^6\) means 2 electrons per \(2p\) orbital, 3 orbitals × 2 = 6).
- \(3s\) orbital: Holds 2 electrons, place "11" in the \(3s\) box.
- \(3p\) orbitals (three orbitals): Each \(3p\) orbital holds 2 electrons, so each of the three \(3p\) boxes gets "11" (since \(3p^6\) means 2 electrons per \(3p\) orbital, 3 orbitals × 2 = 6).
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- \(1s\): \(11\)
- \(2s\): \(11\)
- \(2p\) (each of the three boxes): \(11\)
- \(3s\): \(11\)
- \(3p\) (each of the three boxes): \(11\)
(To apply this, drag the "11" label to each orbital box as per the electron configuration of argon.)