Question

write the following sum as a single logarithm. assume all variables are positive. \\(\log_{4}(4) + \log_{4}(8) = \\) \\(\boxed{}\\) the answer format in lowercase characters is: log_base (number) spaces in the answer are optional. submit question get a similar question you can retry this question below

Explanation:

Step1: Apply log addition rule

$\log_4(4) + \log_4(8) = \log_4(4 \times 8)$

Step2: Calculate product inside log

$4 \times 8 = 32$

Step3: Simplify log expression

$\log_4(32) = \log_{2^2}(2^5) = \frac{5}{2}$

Answer:

$\frac{5}{2}$