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write the equilibrium constant expression for this reaction: h₃po₄(aq) …

Question

write the equilibrium constant expression for this reaction: h₃po₄(aq) → 3h⁺(aq)+po₄³⁻(aq)

Explanation:

Step1: Recall the formula for equilibrium constant

For a reaction \(aA + bB
ightleftharpoons cC + dD\), the equilibrium constant \(K=\frac{[C]^c[D]^d}{[A]^a[B]^b}\), where \([X]\) represents the molar concentration of species \(X\).

Step2: Identify reactants and products

In the reaction \(H_3PO_4(aq)
ightleftharpoons3H^{+}(aq)+PO_4^{3 - }(aq)\), the reactant is \(H_3PO_4\) and the products are \(H^{+}\) and \(PO_4^{3 - }\). The stoichiometric coefficient of \(H^{+}\) is \(3\), of \(PO_4^{3 - }\) is \(1\), and of \(H_3PO_4\) is \(1\).

Step3: Write the equilibrium constant expression

Substitute into the formula: \(K=\frac{[H^{+}]^3[PO_4^{3 - }]}{[H_3PO_4]}\)

Answer:

\(K=\frac{[H^{+}]^3[PO_4^{3 - }]}{[H_3PO_4]}\)